999精品在线视频,手机成人午夜在线视频,久久不卡国产精品无码,中日无码在线观看,成人av手机在线观看,日韩精品亚洲一区中文字幕,亚洲av无码人妻,四虎国产在线观看 ?

LEONARD PAIRS CONSTRUCTED FROM THE QUANTUM ALGEBRA νq(sl2)

2020-02-21 01:27:28LIUJunliXUQiuliJIANGWei
數學雜志 2020年1期

LIU Jun-li, XU Qiu-li, JIANG Wei

(College of Science, Langfang Normal University, Langfang 065000, China)

Abstract: In this paper, we study the construction of Leonard pairs.By using the finite dimensional irreducible representations of quantum algebra νq(sl2), we get Leonard pairs, and give the classification of Leonard pairs, which provide more help in studying Leonard triples.

Keywords: Leonard pair; quantum algebra; irreducible representation; split basis

1 Intro duction

Leonard pairs were introduced by Terwilliger in [1], which gave some examples to illustrate how Leonard pairs arise in representation theory, combinatorics, and the theory of orthogonal polynomials.Because these polynomials frequently arise in connection with the finite-dimensional representations of good Lie algebras and quantum groups, it is natural to find Leonard pairs associated with these algebraic objects.Leonard pairs of Krawtchouk type were described in [2]using split basis and normalized semisimple generators ofsl2.Leonard pairs ofq-Krawtchouk type were described in [3]using split basis ofUq(sl2).Recently,Alnajjar and Curtin in[4]gave general construction of Leonard pairs of Racah,Hahn,dual Hahn and Krawtchouk type using equitable basis ofsl2.Alnajjar in [5, 6]gave general construction of Leonard pairs ofq-Racah,q-Hahn, dualq-Hahn,q-Krawtchouk, dualq-Krawtchouk, quantumq-Krawtchouk, and affineq-Krawtchouk type using equitable generators ofUq(sl2).The Leonard pairs and Leonard triples ofq-Racah type from the quantum algebraUq(sl2)were also discussed by Hou in[7]and[8].Equivalent presentations forUq(sl2)were introduced in [9].

Given a Leonard pair it is often more natural to work with a split basis rather than a standard basis.In this paper, we illustrate this with an example based on the quantum algebraνq(sl2).LetMdenote a finite-dimensional irreducibleνq(sl2)-module and assume A (resp.B) is an arbitrary linear combination ofF,K(resp.EH?1,H?1).We give the necessary and sufficient conditions on the coefficients for A,B to act onMas a Leonard pair.

The rest of this paper are organized as follows.In Section 2, we introduce some facts concerning the Leonard pairs.In Section 3, we recall some facts concerning irreducible finite-dimensionalνq(sl2)-modules.In Section 4, we define two linear transformations A and B using the elements inνq(sl2) and describe their properties.At last, we characterize when the pair A,B is a Leonard pair.

2 Leonard Pairs

In this section,we recall the definitions and some related facts concerning Leonard pairs,and more details about the Leonard pairs can be found in [3].Throughout this paperFdenotes an algebraically closed field.Fix a nonzero scalarq ∈Fwhich is not a root of unity.Md+1(F) denote theF-algebra consisting of all (d+1) by (d+1) matrices having rows and columns indexed by 0,1,2,···,dfor a nonnegative integerd.

LetVdenote aF-vector space of dimensionsd+1.Let End(V) denote theF-algebra consisting of all linear transformations fromVtoV.Letdenote a basis forV.For A∈End(V) andX ∈Md+1(F), we sayXrepresents A with respect towheneverwhereXijis the element in the matrixX.

A square matrix is said to be tridiagonal if each nonzero entry lies on either the diagonal,the subdiagonal, or the superdiagonal.A tridiagonal matrix is said to be irreducible if each entry on the subdiagonal is nonzero and each entry on the superdiagonal is nonzero.We now define a Leonard pair.

Definition 2.1LetVbe a vector space overFwith finite positive dimensions.A Leonard pair onVis an ordered pair of linear transformations A:V →Vand A?:V →Vthat satisfy both the conditions below.

(1) There exists a basis forVwith respect to which the matrix representingAis diagonal and the matrix representingA?is irreducible tridiagonal.

(2) There exists a basis forVwith respect to which the matrix representingA?is diagonal and the matrix representingAis irreducible tridiagonal.

There are so many examples of Leonard pairs which arise in representation theory,combinatorics, and the theory of orthogonal polynomials, for details can be found in [3].

Given a Leonard pair A,A?, it is natural to represent one of A,A?by an irreducible tridiagonal matrix and the other by a diagonal matrix.In order to distinguish the two representations, Terwilliger introduced the standard basis and split basis for this pair in [3].A square matrix is said to be lower bidiagonal whenever every nonzero entry lies on either the diagonal or the subdiagonal.A lower bidiagonal is said to be irreducible lower bidiagonal whenever each entry on the subdiagonal is nonzero.A matrix is upper bidiagonal (resp.irreducible upper bidiagonal) whenever its transpose is lower bidiagonal (resp.irreducible lower bidiagonal).

Definition 2.2LetVdenote a vector space overFwith finite positive dimension and let A,A?denote a Leonard pair onV.A standard basis for this pair is a basis forVwith respect to which the matrix representing A is irreducible tridiagonal and the matrix representing A?is diagonal.

Definition 2.3LetVdenote a vector space overFwith finite positive dimension and let A,A?denote a Leonard pair onV.A split basis for this pair is a basis forVwith respect to which the matrix representing A is irreducible lower bidiagonal and the matrix representing A?is irreducible upper bidiagonal.

The following theorem in [3]provides a way to recognize a Leonard pair.

Theorem 2.4(see [3]) LetVdenote a vector space overFwith finite positive dimension.Let A :Vand B :Vdenote linear transformations.Let us assume there exists a basis forVwith respect to which the matrices representing A and B have the following form

Then the pair A,B is a Leonard pair onVif and only if there exist scalarsφi(1≤i ≤d) inFsuch that conditions (i)–(v) hold below

In the rest of this paper, we use the theorem to get Leonard pairs.

3 νq(sl2)-Modules

In this section, we recall some facts concerning irreducible finite-dimensionalνq(sl2)-modules in [10].

Definition 3.1The quantum algebraνq(sl2)is defined as the associative algebra(with 1 and overF) with the generatorsE,F,K,K?1,H,H?1and the following relations

Lemma 3.2Lett ≥1 be an integer.Then we have the following formulas inνq(sl2),

where (t)q=1+q2+···+q2(t?1).

Lemma 3.3Given an nonnegtative integernanda,b ∈Fwithab=q2n.LetMbe an+1-dimensional vector space with basis{m0,m1,···,mn}.We define theνq(sl2)-action onMas follows

ThenMbecomes aνq(sl2)-module, we denote byM(n,a,b).

Theorem 3.4Suppose that V is a finite dimensional irreducibleνq(sl2)-module with dimensionn+1, thenVis isomorphic toM(n,a,b) for somea,b ∈Fwithab=q2n.

We describe the construction of Leonard pairs fromνq(sl2)-modules by using generators ofνq(sl2) in the next section.

4 Leonard Pairs From νq(sl2)

In this section, we define two linear transformations A and B of elements inνq(sl2) and characterize when the pair A,B is a Leonard pair.

Definition 4.1Referring to Definition 3.1 and Lemma 3.3 , letα,βdenote nonzero scalars inF.Then define two linear transformations A,B as follows

Now we give the main result in this paper.

Theorem 4.2Letnbe an nonnegative integer anda,b ∈Fwithab=q2n.Then the pair A,B defined in (4.1) acts onM(n,a,b) as a Leonard pair providedαβis not amongq?2,q?4···,q?2n.

To prove the above theorem, we apply Theorem 2.4.Before do this, we first give some lemmas.

Lemma 4.3There exists a basis forM(n,a,b) with respect to which the matrices representing A, B have the form of (2.1).

ProofWe can obtain this basis by modifying the basis{m0,m1,···,mn} given in Lemma 3.3.For 0≤i ≤n, we defineui=αimi.We observe{u0,u1,···,un} is a basis forM(n,a,b).The elementsE,F,K,Hact on this basis as follows

Takeab=q2ninto (4.2), we can get the coefficient ofui?1as below

Using these comments we can get

whereu?1=un+1= 0.Thus, with respect to the basis{u0,u1,···,un} the matrices representing A, B are given in (2.1), where

Lemma 4.4Referring to Lemma 4.3, the following two equations hold

ProofImmediate from Lemma 4.3 and a simple calculation.

Lemma 4.5Referring to Lemma 4.3, the scalarsθialso satisfy the following equation

ProofUsing the sum of the geometric progression, we have

Then from (4.4), equation (4.3) holds.

Proof of Theorem 4.1Defineφi=(i)q(n ?i+1)q(αβ ?q?2(n?i+1)),1≤i ≤n.Let us assumeαβis not amongq?2,q?4···,q?2n.Then the above scalarssatisfy conditions (i)–(v) of Theorem 2.4 by Lemmas 4.3, 4.4 and 4.5.

Remark 1Applying Theorem 2.4 we find the pair A, B acts onM(n,a,b) as a Leonard pair.With respect to the basis{u0,u1,···,un}, the matrix representing A (resp.B) is irreducible lower bidiagonal (resp.irreducible upper bidiagonal).Therefore this basis is a split basis for A, B in view of Definition 2.3.

Remark 2By the classification of Leonard pairs in [11], those with=q2+q?2+1 are the familiesq-Racah,q-Hahn,dualq-Hahn,quantumq-Krawtchouk,affineq-Krawtchouk,q-Krawtchouk,or dualq-Krawtchouk,and since the pair A,B has this property(see Lemma 4.4), it’s easy to show that this pair is of quantumq-Krawtchouk type.

主站蜘蛛池模板: 欧美成人综合视频| 欧美中日韩在线| 热99精品视频| 国产在线精品网址你懂的 | 亚欧乱色视频网站大全| 欧美在线中文字幕| 国内精品91| 成人免费视频一区二区三区| 中文字幕在线看视频一区二区三区| 日韩欧美中文字幕在线韩免费| 亚洲综合色婷婷| 香蕉伊思人视频| 网友自拍视频精品区| 国产v精品成人免费视频71pao| 久久九九热视频| 国产高清不卡视频| 精品国产一区二区三区在线观看 | a级毛片毛片免费观看久潮| 啦啦啦网站在线观看a毛片| 美女国内精品自产拍在线播放| 成人字幕网视频在线观看| 久久精品亚洲中文字幕乱码| 午夜国产精品视频| 40岁成熟女人牲交片免费| 国产欧美精品一区二区| 欧美特黄一免在线观看| 国产成人欧美| 日韩a级片视频| 国产欧美一区二区三区视频在线观看| 欧美精品综合视频一区二区| 这里只有精品在线播放| 亚洲av无码久久无遮挡| 久久精品国产精品青草app| 国产精品一区二区在线播放| 色网站免费在线观看| 无遮挡一级毛片呦女视频| 色色中文字幕| 欧美日韩国产高清一区二区三区| 男女男精品视频| 亚洲系列无码专区偷窥无码| 日本一区高清| A级毛片高清免费视频就| 亚洲日韩高清在线亚洲专区| 国产精品无码一区二区桃花视频| 99视频在线免费观看| 性欧美在线| 女人一级毛片| 一区二区在线视频免费观看| 超碰91免费人妻| 999精品在线视频| 十八禁美女裸体网站| 国产一区二区三区在线观看免费| 日本一区二区三区精品视频| 国产高清色视频免费看的网址| 日韩123欧美字幕| 专干老肥熟女视频网站| 亚洲欧美综合精品久久成人网| 欧美第九页| 国产成人精品无码一区二| 曰韩免费无码AV一区二区| 女人18毛片久久| 国产黑丝视频在线观看| 亚洲国产第一区二区香蕉| 亚洲AⅤ无码国产精品| 中文字幕久久波多野结衣| 亚洲第一区欧美国产综合| 亚洲无码高清一区二区| 欧美成人日韩| 亚洲综合第一页| 久久国产免费观看| 在线观看免费AV网| 亚洲性视频网站| 国产成人精彩在线视频50| 中国一级毛片免费观看| 999在线免费视频| 国产制服丝袜91在线| 国产青青草视频| 国产簧片免费在线播放| 午夜成人在线视频| 91精品国产91久无码网站| 亚洲另类国产欧美一区二区| 久久久久亚洲精品成人网|