999精品在线视频,手机成人午夜在线视频,久久不卡国产精品无码,中日无码在线观看,成人av手机在线观看,日韩精品亚洲一区中文字幕,亚洲av无码人妻,四虎国产在线观看 ?

ON (a ,3)-METRICS OF CONSTANT FLAG CURVATURE*

2023-01-09 10:53:58GuangzuCHEN陳光祖

Guangzu CHEN (陳光祖)

School of Science,East China JiaoTong Uniuersity,Nanchang 330013,China E-mail : chenguangzu1@163.com Xinyue CHENG(程新躍)*

School of Mathematical Sciences,Chongqing Normal Universitg,Chongqing 401331,China E-mail: chengxy@cqnu.edu.cn

The study of Finsler metrics of constant flag curvature has a long history. In 1977, H.Yasuda and H. Shimada studied the classification problem on Randers metrics of constant flag curvature([12]). Later,D.Bao,C.Robles and Z.Shen completely classified Randers metrics of constant flag curvature by using the navigation technique([3]). Furthermore,R.Yoshikawa and S. V. Sabau obtained the classification theorem on Kropina metrics of constant flag curvature([8]). In addition to this, L. Zhou proved that the square metrics of constant flag curvature must be projectively flat ([13]). In [11], Shen-Yildirim classified the projectively flat square metrics of constant flag curvature. Thus the local constructions of square metrics of constant flag curvature have been determined completely. However,the local constructions of the(α,β)-metrics of constant flag curvature are still not clear,except for Randers metrics,Kropina metrics and square metrics.

For the discussions that follow, we need to clarify some notations for (α,β)-metrics. Let

Furthermore, put

where“|”denotes the covariant derivative with respect to α. Let s0:=siyi, si0:=sijyj, r00:=rijyiyj, etc.. We say that β is a homothetic 1-form with respect to α if rij= caij, where c is a constant. We say that β is a Killing 1-form with respect to α if c=0. When c/=0, we have the following theorem:

Theorem 1.1 Let F =αφ(β/α) be an almost regular (α,β)-metric of non-Randers type on a manifold M. Suppose that β is a homothetic 1-form with respect to α satisfying that

It is easy to see that b= constant if and only if ri+si=0. If rij=0 and si=0, then β is a Killing 1-form with constant length. In this case, we have the following result:

Theorem 1.2 Let F = αφ(β/α) be a regular (α,β)-metric of non-Randers type on a manifold M. Suppose that F is of constant flag curvature and that β is a Killing 1-form with constant length. Then F must be a locally Minkowskian.

From the proof of Theorem 1.2, the following is obvious:

Corollary 1.3 Let F = αφ(β/α) be a regular (α,β)-metric on a manifold M. Suppose that F is of constant flag curvature and that β is a Killing 1-form with constant length. Then F must be a Riemannian metric or locally Minkowskian.

2 Preliminaries

Let F be a Finsler metric on an n-dimensional manifold M. The geodesic coefficients Giof F are defined by ([5])

According to Deicke’s theorem, a Finsler metric is Riemannian if and only if the mean Cartan torsion vanishes ([10]).

and

By a direct computation, we can obtain the following formula about the mean Cartan torsion of (α,β)-metric F ([4]):

3 The Discussions About Equation (2.4)

When a Finsler metric F is of constant flag curvature K, (2.4) becomes

Now we assume that β is a homothetic 1-form,that is,that rij=caij,where c is a constant,so

Then, by (3.6)-(3.12), we have the following result:

Proposition 3.1 Let F = αφ(β/α) be an almost regular (α,β)-metric of constant flag curvature. Suppose that β is a homothetic 1-form with rij=caij. Then it holds that

Plugging (3.10), (3.12), (3.19) and (3.18) into (3.6) and by using the Maple program, we can get (3.13) easily. □

4 Discussion of Equation (2.12)

Let F = αφ(β/α) be an (α,β)-metric on a manifold M. Suppose that β is a homothetic 1-form, that is, rij=caij, where c is a constant. It follows from (2.7), (2.10) and (2.11) that

When F is of constant flag curvature K, then substituting (4.3)-(4.7) into (2.12), we can get the following proposition:

Proposition 4.1 Let F =αφ(β/α)be an almost regular(α,β)-metric with a homothetic 1-form β on a manifold M. If F is of constant flag curvature, then it holds that

5 Proof of Theorem 1.1

First, we will give some necessary lemmas.

Lemma 5.1 Let F = αφ(β/α) be an (α,β)-metric of non-Randers type on a manifold M. If φ=φ(s) satisfies that

where C1and C2are constant.

Furthermore, we have the following lemma:

Lemma 5.3 Let F = αφ(β/α) be an almost regular (α,β)-metric of non-Randers type on a manifold M. Suppose that

where c is a non-zero constant. If F is of constant flag curvature,then β is closed and φ satisfies that

which implies that Λ = k(B)φ. It follows from (5.9) and Lemma 5.2 that [k(B)]B= 0, which implies that k(B) is a constant. By Lemma 5.1, we get r0+s0=0, which contradict the fact that c/=0. Thus sQΛs+Λs-QΛ/=0. Then (5.10) implies that sij=0. □

Now we are in the position to prove Theorem 1.1. Under the conditions of Theorem 1.1,by Lemma 5.3, equation (1.2) holds and β is closed. Thus we only need to prove that equation(1.3) holds.

6 Proof of Theorem 1.2

which contradicts the assumption by Lemma 6.1. Thus K = 0. It follows from (6.4) that si0si0=0, that is, that aijsi0sj0=0. Then we have sij=0. In this case, rij=sij=0, which implies, by (2.7), that F is a Berwald metric. Hence F is locally Minkowskian. □

7 An Example

Usually, it is difficult to solve (1.2). In this section, we will determine the solution of(1.2) under the condition that Λ=f(s)g(B), where f(s) and g(B) are non-constant functions depending only on s and B, respectively.

First, when Q'=0, it is easy to check that

where λ is a non-zero constant and a=(ai) is a constant vector in Rn. In this case,

which means that (1.1) holds. Furthermore, we can check that φ=1/s satisfies equation(1.2).In fact, it is easy to see that φ = 1/s also satisfies equation (1.3) with k = 0. The metric F = α2/β is called a Kropina metric. The Kropina metrics of constant flag curvature have been classified in [8].

主站蜘蛛池模板: 蜜桃臀无码内射一区二区三区| 亚洲va视频| 人与鲁专区| 久久久久久久久久国产精品| 亚洲成肉网| 中文字幕一区二区人妻电影| 五月六月伊人狠狠丁香网| 18禁色诱爆乳网站| 99久久精品视香蕉蕉| 97国产在线播放| 亚洲中文无码av永久伊人| 伊人成色综合网| 国产丝袜无码一区二区视频| 国产成人艳妇AA视频在线| 激情无码视频在线看| 永久免费无码成人网站| 亚卅精品无码久久毛片乌克兰 | 国产成人精品免费视频大全五级| 亚洲码在线中文在线观看| 青青草国产精品久久久久| 国产jizz| 黄色免费在线网址| 国产无码性爱一区二区三区| 亚洲综合色吧| 精品人妻无码中字系列| 亚洲视频三级| 国产精品99久久久久久董美香| 久久久91人妻无码精品蜜桃HD| 伊在人亞洲香蕉精品區| 欧美亚洲日韩中文| 风韵丰满熟妇啪啪区老熟熟女| 久久久久亚洲AV成人网站软件| 欧美日韩福利| 天天综合天天综合| 亚洲美女高潮久久久久久久| 亚洲看片网| 亚洲综合网在线观看| 国产婬乱a一级毛片多女| 日韩第九页| 91偷拍一区| 国产视频你懂得| 无码不卡的中文字幕视频| 国产欧美日韩免费| 99久久成人国产精品免费| 特级毛片8级毛片免费观看| 在线观看91香蕉国产免费| 在线五月婷婷| 国产欧美日韩另类精彩视频| 韩日午夜在线资源一区二区| 久久免费观看视频| www.99精品视频在线播放| 无码视频国产精品一区二区| 国模粉嫩小泬视频在线观看| 日韩不卡高清视频| 麻豆国产精品| 欧美成人亚洲综合精品欧美激情| 免费亚洲成人| 97国产在线视频| 日本精品一在线观看视频| 中日韩一区二区三区中文免费视频| 久久国产av麻豆| 国产99免费视频| 久久精品人人做人人爽97| 成人福利在线免费观看| 欧美精品二区| 亚洲天堂网视频| 精品福利一区二区免费视频| 亚洲人精品亚洲人成在线| 2021国产精品自产拍在线| 四虎精品国产永久在线观看| 亚洲精品久综合蜜| 91精品国产一区自在线拍| 久久99精品国产麻豆宅宅| 精品国产免费观看一区| 国产亚洲一区二区三区在线| a级毛片免费播放| 美女啪啪无遮挡| 久久久无码人妻精品无码| 亚洲av无码成人专区| 欧洲亚洲一区| 欧美激情第一欧美在线| 一级黄色网站在线免费看|